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Solving the Sum of Three Consecutive Even Integers Problem
Solving the Sum of Three Consecutive Even Integers Problem
Solving problems involving consecutive even integers is a common task in arithmetic and algebra. This article will walk you through the process of solving the specific problem: What are three consecutive even integers whose sum is 246?
Method 1: Using Basic Algebra
Let n be the first of these even integers. Since the integers are consecutive and even, the second number will be n 2, and the third will be n 4. The sum of these three integers is given as 246.
Using this information, we can write the equation:
n (n 2) (n 4) 246
Combining like terms, we get:
3n 6 246
Solving for n by first subtracting 6 from both sides:
3n 240
Then, dividing by 3:
n 80
Therefore, the three consecutive even integers are 80, 82, and 84.
Method 2: Logical Deduction
An alternative approach is to use the concept of the middle number. Since the average of the three numbers is 246/3 82, 82 must be the middle number. Thus, the three consecutive even integers are 80, 82, and 84.
Method 3: Another Algebraic Approach
Assume the numbers are represented by x, x 2, x 4. The sum of these numbers is:
x (x 2) (x 4) 246
Combining like terms, we get:
3x 6 246
Solving for x by first subtracting 6 from both sides:
3x 240
Then, dividing by 3:
x 80
Therefore, the three consecutive even integers are 80, 82, and 84.
Method 4: Substitution Method
Assume the three consecutive even integers are 2X, 2X 2, 2X 4. The sum of these integers is:
2X (2X 2) (2X 4) 246
Combining like terms, we get:
6X 6 246
Solving for X by first subtracting 6 from both sides:
6X 240
Then, dividing by 6:
X 40
Therefore, the three consecutive even integers are 80, 82, and 84.
Method 5: Using an Alternative Variable
Assume the consecutive even integers are X - 2, X, X 2. The sum of these integers is:
(X - 2) X (X 2) 246
Combining like terms, we get:
3X 246
Solving for X by dividing by 3:
X 82
Therefore, the three consecutive even integers are 80, 82, and 84.
These methods provide a comprehensive approach to solving the problem and demonstrate the flexibility in solving such arithmetic problems.